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Unit 7 test

Unit 7 · Unit 7 end-of-unit test (also the test-out)

Suggested time: about 80 minutes. Answer everything, then press Submit the test to see the feedback and scoring guides.

Answer every question, then press Submit the test. Feedback and the scoring guides appear after you submit. For the three free-response questions, write one short sentence for each step of your reasoning, each on its own line, and make every link clear (so, because, therefore). That is what the exam’s ‘paragraph form’ means for you: linked sentences, not bullet points. After you submit, mark your own free-response work against each scoring guide. Suggested time: 80 minutes. Every count, frequency, date and sequence reading in this test is imagined for the question unless the question says otherwise; the trees show real relationships.
Question 1

Researchers follow every male cardinal in one wood through a breeding season and record several quantities for each male.

Which of the following quantities measures a male’s evolutionary fitness?

Question 2

A magazine article says: “Over thousands of years, the oryx of the desert developed the ability to last for weeks on the water in its food so that it could survive the dry season.”

Which of the following rewrites the sentence so that it describes natural selection?

Question 3
A table of the plants that set seed at two sites, 50 of each leaf form sown at each site: dry ledge, 38, 14; damp gully, 15, 36sitehairy-leaved plants that set seed, of 50smooth-leaved plants that set seed, of 50dry ledge3814damp gully1536
The plants of each leaf form that set seed at the two sites, out of 50 sown.

A saxifrage of one kind grows on a mountain. Its plants have either hairy leaves or smooth leaves, and the difference is heritable. Researchers sow 50 seeds of each form on a dry rock ledge and 50 of each in a damp gully, and count the plants of each form that set seed, as the table shows.

Seeds collected on the dry ledge, where most plants are hairy-leaved, are sown in a damp gully. Predict how the two forms’ shares change there over several generations.

Question 4

Sea lavender grows on a saltmarsh. Its root cells pump salt out. Plants vary in how many copies of the pump protein each root cell makes, and the number is set by alleles. Rising sea levels bring saltier water farther up the marsh.

Which of the following best explains how natural selection can act on the number of pump proteins in a root cell?

Question 5

In a petunia line, dwarf stems are set by a recessive allele d and tall stems by the dominant allele D. A breeder wants every plant in her line to be dwarf as soon as possible. About 25% of her plants are dwarf this year.

Which of the following breeding plans gives a line of dwarf plants only in the fewest generations?

Question 6
A table of the number of different alleles found per gene at five genes, in 200 wild teff plants and in 200 plants of the bred line: grain size, 6, 2; leaf shape, 5, 2; flowering time, 4, 1; a cell-surface protein, 7, 3; a root enzyme, 5, 2genedifferent alleles found: 200 wild plantsdifferent alleles found: 200 bred-line plantsgrain size62leaf shape52flowering time41a cell-surface protein73a root enzyme52
The number of different alleles found per gene at five genes, in 200 wild teff plants and in 200 plants of the bred line.

Breeders start a line of teff, a grain, from a wild population. For ten generations they grow 200 plants and breed only from the 8 plants with the largest grains. Then researchers read five genes in 200 plants of the bred line and in 200 wild plants, and count the different alleles they find at each gene, as the table shows.

Which of the following explains the pattern in the table?

Question 7
A table of the genotype counts of 50 juncos at a plumage gene with alleles W and w: number of juncos, 8, 24, 18genotypeWWWwwwnumber of juncos82418
The genotype counts of 50 juncos at the plumage gene.

Biologists genotype 50 juncos, small birds, from one hillside at a plumage gene with two alleles, W and w. The table gives the counts.

Which of the following is the frequency of allele w in this sample?

Question 8

A pond holds a large population of bluegill, a fish. During a flood, 25 bluegill are swept over a dam into a reservoir downstream that had no bluegill. Which fish were swept over did not depend on their alleles. Ten years later the reservoir holds 3,000 bluegill, and their allele frequencies at several genes differ from the pond’s.

Which of the following best describes the process that set the reservoir population’s allele frequencies?

Question 9
A table of the resident and the arriving walleye: the number of fish, their copies of the gene and their copies of allele G: residents, 80, 160, 120; arrivals, 20, 40, 4walleyecopies of the genecopies of allele Gresidents80160120arrivals20404
The resident and the arriving walleye: fish, copies of the gene and copies of allele G.

A lake holds 80 walleye, a fish. At one gene with two alleles, G and g, the residents hold 120 copies of G. Then 20 walleye from a hatchery are released into the lake and breed with the residents. The table gives the copies each group holds.

Which of the following is the frequency of G in the lake population after the arrivals join?

Question 10

Isopods, small crustaceans, live in the leaf litter on both sides of a four-lane highway. Researchers propose that the highway blocks gene flow between the two sides. They genotype 100 isopods from each side and compare the allele frequencies, and they do the same for two groups 100 m apart on the same side.

Which of the following is the null hypothesis for this study?

Question 11

Suppose 4% of the 500 campion plants on a cliff have white flowers. White (w) is recessive to pink (W), the plants mate at random, and no force acts on this gene.

Which of the following is the expected number of Ww plants, the carriers?

Question 12
A line graph of the frequency of allele B against generation, 0 to 7, with two lines: reef J and reef K; gridlines every 0.100.20.40.60.8101234567generationfrequency of allele Bgridlines every 0.1reef Jreef K
The frequency of allele B on reef J and on reef K, generation 0 to generation 7.

Biologists follow the frequency of allele B in the damselfish of two reefs, J and K, for seven generations, as the graph shows.

Which reef’s allele frequency at this gene is consistent with Hardy–Weinberg equilibrium?

Question 13
A table of the observed and the expected genotype counts of 200 swordtails at a fin gene with alleles S and s: observed SS 104, Ss 72, ss 24; expected SS 98, Ss 84, ss 18; all the fish 200 and 200SSSsssall the swordtailsobserved count, o1047224200expected count, e988418200expected counts from the census’s own allele frequencies, p = 0.70 and q = 0.30
The observed and the expected genotype counts of the 200 swordtails.

Biologists genotype 200 swordtails, a fish, from one stream at a fin gene with alleles S and s. The table shows the observed counts above the counts the Hardy–Weinberg model expects from the census’s own allele frequencies.

Which of the following is chi-square for the three genotype classes?

Question 14

A lagoon holds 3,000 mullet, a fish. At one gene the frequency of allele T is 0.30. A storm drains most of the lagoon, and 40 mullet survive in one pool; which mullet survived did not depend on their alleles. Among the 40 survivors the frequency of T is 0.45. The survivors breed and the lagoon refills.

Which of the following Hardy–Weinberg conditions did the storm break?

Question 15

A layer of volcanic rock holds a slow isotope with a half-life of 700 million years. 25% of the isotope the rock held when it formed is still left.

How old is the rock?

Question 16
A table of the same 10 amino acids of one hypothetical protein in four birds, the dipper the reference in the first row: dipper: Met Gly Lys Val Ala Ser Leu Thr Glu Phe; tanager: Met Gly Lys Ile Ala Ser Leu Thr Glu Phe; vireo: Met Ala Lys Ile Ala Ser Leu Thr Asp Phe; osprey: Met Ala Arg Ile Ala Thr Leu Ser Asp Pheposition12345678910dipperMetGlyLysValAlaSerLeuThrGluPhetanagerMetGlyLysIleAlaSerLeuThrGluPhevireoMetAlaLysIleAlaSerLeuThrAspPheospreyMetAlaArgIleAlaThrLeuSerAspPhe
The same 10 amino acids of one hypothetical protein in four birds; the dipper is the reference.

A lab reads the same 10 amino acids of one protein in four birds. The table shows the four readings; the dipper is the reference species, and the protein is hypothetical.

Which bird shares the most recent common ancestor with the dipper?

Question 17
A table of four forms in one line of descent, the oldest fossil first and the living aardvark last: age in million years and forelimb claw length in centimeters: 30, 2; 20, 4; 10, 6; living aardvark, 8age of the fossil (million years)forelimb claw length (cm)302204106living aardvark8
Four forms in one line of descent: the age of each fossil and its forelimb claw length; the living aardvark last.

Suppose fossils of one line of digging mammals lie in dated rock layers, and the living aardvark is the last member of the line. The table gives each form’s age and the length of the claws on its forelimbs.

Which of the following conclusions do the fossils support?

Question 18

Two groups of single-celled organisms from two ponds both have rounded cells. A student says: “The two groups share a rounded cell shape, so they must share a recent common ancestor.”

Is the student correct?

Question 19
A table of four newly found single-celled organisms, named by where they were found, with three features each: the mudflat cell, yes, several molecules, each with two free ends, yes; the ice cell, no, one closed loop, no; the vent cell, yes, one closed loop, yes; the soil cell, no, several molecules, each with two free ends, nofinda nucleusthe main DNAintrons in its genesthe mudflat cellyesseveral molecules, each with two free endsyesthe ice cellnoone closed loopnothe vent cellyesone closed loopyesthe soil cellnoseveral molecules, each with two free endsno
Four newly found single-celled organisms and three features of each.

Biologists describe four newly found single-celled organisms, as the table shows.

Which find, if confirmed, would challenge the claim that all eukaryotes descend from one ancestor?

Question 20

A farmer sprays a field of dock, a weed, with a herbicide for the first time. Students find the share of dock plants carrying an allele for surviving the herbicide before the spray, 0.05, and among the plants alive two weeks after it, before any of them has set seed, 0.65. They conclude that the dock population has evolved resistance.

What is the flaw in the students’ conclusion?

Question 21
A table of goldenrod specimens kept from three years: the year collected, the specimens measured and the mean flower-head diameter in millimeters: 1964, 80, 14.8; 1994, 80, 14.9; 2024, 80, 14.8year collectedspecimens measuredmean flower-head diameter (mm)19648014.819948014.920248014.8
Goldenrod specimens from three years: the specimens measured and their mean flower-head diameter.

A museum keeps goldenrod specimens collected from one coastal headland in 1964, 1994 and 2024. Researchers measure the flower heads of 80 specimens from each year, as the table shows, and conclude that the goldenrod population has stopped evolving.

Is the researchers’ conclusion supported by the data?

Question 22
A table with 5 columns headed clubmoss, cycad, lupin, dahlia, yarrow (the clubmoss's column shaded), and 3 rows: seeds: no, yes, yes, yes, yes; flowers: no, no, yes, yes, yes; flowers grouped into one composite head: no, no, no, yes, yes; each cell reads yes or noclubmosscycadlupindahliayarrowseedsnoyesyesyesyesflowersnonoyesyesyesflowers grouped into one composite headnononoyesyes
Three characters of five plants; the clubmoss is the outgroup.

The table gives three characters of five plants. The clubmoss is the outgroup. Biologists build a cladogram from the table.

Which plant do biologists add to the cladogram first after the outgroup?

Question 23

Biologists compare one stretch of DNA in two kinds of coati, a mammal of the Americas, and find 15 differences. From fossil-dated splits among the coatis’ relatives they set the rate at 2.5 differences per million years, and they treat the rate as roughly steady. The count and the rate are imagined.

About how long ago did the two coati lineages split?

Question 24
A cladogram of 4 primates, mandrill, langur, orangutan, loris; the root at the bottom and the tips level along the top; the branch points drawn as dotsmandrilllangurorangutanloris
A cladogram of four primates.

The cladogram shows four primates.

Which primate is the most closely related to the langur?

Question 25

Suppose four pairs of populations are kept apart by four different barriers, one in each case.

Which of the following barriers is a pre-zygotic mechanism?

Question 26

Suppose a plant of one kind holds 22 chromosomes in each body cell. On one grassy riverbank a failure of meiosis gives rise to plants with 44 chromosomes. The 44-chromosome plants grow beside their 22-chromosome parents, flower in the same weeks, and are visited by the same bees. Crosses between the two kinds give healthy plants with 33 chromosomes that set no seed.

Which of the following best explains how the 44-chromosome plants became cut off from the 22-chromosome plants?

Question 27
A table of ten rock layers, layer 1 the bottom layer, each with the mean height of the necklace shells in it, in millimeters: 1, 8.0; 2, 8.4; 3, 8.9; 4, 9.3; 5, 9.8; 6, 10.2; 7, 10.7; 8, 11.1; 9, 11.6; 10, 12.0layermean shell height (mm)18.028.438.949.359.8610.2710.7811.1911.61012.0
The mean height of the necklace shells in each of the ten layers; layer 1 is the bottom layer.

Suppose necklace shells, sea snails with a rounded shell, left shells in every layer of an undisturbed column of ten rock layers. Layer 1 is the bottom layer. Biologists measure about 50 shells from each layer; the table gives each layer’s mean shell height.

Which tempo does this record show?

Question 28
A table of three chough populations, one per glen: the number of choughs, the number of alleles at one gene and the share of choughs heterozygous at that gene: Basalt Glen, 2,050, 2, 6%; Cairn Glen, 125, 9, 52%; Shale Glen, 640, 5, 30%populationchoughsalleles at one genechoughs heterozygous at that geneBasalt Glen2,05026%Cairn Glen125952%Shale Glen640530%
The three chough populations: birds, alleles at one gene and the share heterozygous at that gene.

Suppose choughs, crow-like birds, nest in three glens. The table gives each population’s size, its number of alleles at a typical gene and the share of its birds heterozygous at that gene. A new disease of crows reaches all three glens.

Which population is the most likely to lose every one of its birds to the disease?

Question 29

Suppose geologists find a stromatolite in a layer of rock now on land, about 2,950 million years old. The iron minerals in the same layer are dark and unrusted. Free oxygen began to build up in the air and sea about 2,400 million years ago.

Which of the following conclusions do the two finds together support?

Question 30

Under the RNA world hypothesis, RNA could have been the earliest genetic material, because an RNA molecule can carry a copyable sequence and, folded up, speed up a reaction.

Which of the following findings, if made, would be evidence against the hypothesis?

How to tackle the free-response questions. Read the verb first: describe asks what you see or know; explain asks why or how, so name the mechanism; predict asks what will happen and why; justify asks for the evidence that supports a claim. Each point is earned by one idea, stated in a sentence that names the thing and the mechanism. Extra words earn nothing; a wrong extra can lose the point. If there is a figure or table, use what it shows. When you finish, check the box for each point your answer earns and compare your sentences with the full-credit answer.
Free response 1 · Interpreting and Evaluating Experimental Results · 9 points
Suppose male pupfish, small fish of desert springs, are either bright blue or dull gray, and the color is set by alleles. Wading birds hunt pupfish in shallow water. Researchers set up four pools, two with bare bottoms and two planted with dense water plants. Into each pool they release 100 males, 50 bright and 50 dull, with females. Over one pool of each kind they stretch a net that keeps wading birds out; the other two pools are open. After one season they count the surviving males and the bright males among them, as the table shows. The counts are imagined.
A table of the four pools: the pool's plant cover, whether wading birds were present or excluded by a net, the males released, the bright males released, the males surviving, the bright males surviving and the share of the survivors that are bright: bare, present, 100, 50, 40, 8, 0.20; bare, excluded by a net, 100, 50, 90, 45, 0.50; planted, present, 100, 50, 60, 27, 0.45; planted, excluded by a net, 100, 50, 90, 44, 0.49poolwading birdsmales releasedbright releasedmales survivingbright survivingbright share of survivorsbarepresent100504080.20bareexcluded by a net1005090450.50plantedpresent1005060270.45plantedexcluded by a net1005090440.49
The four pools: plant cover, whether wading birds were present, the males released and surviving, and the share of the survivors that are bright.

(a)(i) Describe the source of the variation in male color that natural selection acts on in the pupfish population. (1 point)

A full-credit answer: The alleles for bright and for dull color first arose by mutation.
Sexual reproduction shuffles them into new combinations, so males differ in color.
The difference is set by alleles, so it is heritable.

Check the box for each point your answer earns

Accept: ‘heritable variation in color that arose by mutation’.

Common slip: Naming the birds as the source. The birds sort the variation; they do not make it.

(a)(ii) Explain why a male’s color affects his evolutionary fitness in a pool where wading birds hunt. (1 point)

A full-credit answer: Wading birds hunt by sight in shallow water.
A bright blue male is easier to see than a dull one, so the birds take bright males more often.
A male that is eaten before he breeds leaves fewer offspring.
So bright color lowers a male’s fitness where birds hunt.

Check the box for each point your answer earns

Scoring note: ‘bright males die more’ with no link to reproduction does not earn the point.

(b)(i) Identify an independent variable in the experiment. (1 point)

A full-credit answer: Whether wading birds were present or excluded by a net.

Check the box for each point your answer earns

Accept one of the following: the presence or absence of wading birds (open or netted); the presence or absence of plant cover in the pool (bare or planted).

Common slip: Naming the share of bright males. That is what the researchers measured, the dependent variable.

(b)(ii) Identify a negative control in the experiment. (1 point)

A full-credit answer: The netted pools, where no birds could hunt.

Check the box for each point your answer earns

Accept one of the following: the netted pools; the netted bare pool; the netted planted pool.

(b)(iii) Justify the researchers’ inclusion of a netted pool of each kind. (1 point)

A full-credit answer: A netted pool shows how bright and dull males survive when no bird hunts in a pool of that kind.
So a change in the open pool of the same kind can be attributed to the birds, not to the bare or planted pool itself.

Check the box for each point your answer earns

Scoring note: ‘it is the control’ with no purpose stated does not earn the point.

Common slip: Writing ‘it is the control’ and stopping. The point needs what the netted pool shows: the share of bright males with no birds hunting.

(c)(i) Based on the data, describe the effect of the wading birds on the share of bright males. (1 point)

A full-credit answer: In the bare pools the birds cut the share of bright males from 0.50 to 0.20.
In the planted pools the birds cut it only from 0.49 to 0.45.

Check the box for each point your answer earns

Accept one of the following: the birds lower the share of bright males (0.50 to 0.20 in the bare pools); the birds lower the share far more in the bare pools than in the planted pools (0.20 against 0.45).

Scoring note: a direction is required; ‘the birds change the share’ does not earn the point.

(c)(ii) Calculate the percent change in the share of bright males in the open bare pool compared with the netted bare pool, giving a fall as a negative value. (1 point)

%

Write down the values in the question:

share in the open bare pool (new) = 0.20
share in the netted bare pool (old) = 0.50

Write down the equation:

percent change=new−oldold×100

Substitute the values into the equation:

percent change=0.20−0.500.50×100=−60%

A full-credit answer: The share is 0.20 in the open bare pool and 0.50 in the netted bare pool.
(0.20 − 0.50) ÷ 0.50 × 100 = −60%.

(d)(i) The survivors in the open bare pool breed, and their offspring grow up in the same pool with the same birds. Predict how the share of bright males changes over the next several generations. (1 point)

A full-credit answer: The share of bright males keeps falling, toward zero.

Check the box for each point your answer earns

Scoring note: accept ‘falls, then levels off at a low share’ where the student argues that bright color also helps a male win a mate.

Common slip: Predicting a return to 0.50. Nothing restores the alleles of the males the birds took; the birds remove bright males every generation.

(d)(ii) Justify your prediction. (1 point)

A full-credit answer: Color is set by alleles, so the mostly dull survivors pass on mostly alleles for dull color.
Each generation the birds take the bright males before they breed.
So fewer alleles for bright color are passed on each generation, and the share of bright males keeps falling.

Check the box for each point your answer earns

Free-response score: 0 of 9
Free response 2 · Analyze Model or Visual Representation · 4 points
Biologists compare whole mitochondrial DNA sequences of four sea cows, the West Indian manatee, the Amazonian manatee, the African manatee and the dugong, and build the phylogenetic tree in Figure 1; its scale gives the time since each split in millions of years. The dates are imagined for this question. They then compare one protein of the blood in the same four animals and count the amino-acid positions at which each pair differs, as Table 1 shows; the counts are imagined.
Above, headed Figure 1, A tree of 4 sea cows, West Indian manatee, Amazonian manatee, African manatee, dugong, drawn on its side with the root at the left and the tips down the right; a scale along the bottom runs from 0 at the right to 30 at the left, labeled millions of years ago; the branch points drawn as dots. Below, headed Table 1, A table of the number of amino-acid positions that differ in one protein between each pair of 4 kinds, West Indian manatee, Amazonian manatee, African manatee, dugong: Amazonian manatee and West Indian manatee 6; African manatee and West Indian manatee 1; dugong and West Indian manatee 12; African manatee and Amazonian manatee 7; dugong and Amazonian manatee 13; dugong and African manatee 12Figure 1. Tree from whole mitochondrial DNA sequences051015202530millions of years agoWest Indian manateeAmazonian manateeAfrican manateedugongTable 1. Amino-acid differences in one protein (imagined counts)West Indian manateeAmazonian manateeAfrican manateeAmazonian manatee6African manatee17dugong121312
Figure 1, a phylogenetic tree of the four sea cows built from whole mitochondrial DNA, with a scale in millions of years ago; Table 1, the amino-acid differences in one protein between each pair.

(a)(i) Estimate, to the nearest million years, the age of the most recent common ancestor of the West Indian manatee and the Amazonian manatee. Answers within 1 million years are accepted. (1 point)

million years

A full-credit answer: The node joining the two manatees sits a little short of the 5 mark on the scale.
So their most recent common ancestor lived about 4 million years ago.

(a)(ii) Identify the sea cow whose lineage split from the others first. (1 point)

A full-credit answer: The dugong.

Check the box for each point your answer earns

Common slip: Naming the African manatee. Its line joins the other manatees at 12 million years; the dugong’s joins only at the root, 25 million years ago.

(b) Determine which two sea cows a tree built from the protein counts in Table 1 alone would place as the most closely related, and state what in the table your decision rests on. (1 point)

A full-credit answer: The West Indian manatee and the African manatee.
Their count, 1, is the smallest in the table, and the pair with the fewest differences is joined at the node nearest the tips.

Check the box for each point your answer earns

(c) Justify the claim that the tree built from whole mitochondrial DNA sequences is more reliable than a tree built from the protein counts in Table 1. (1 point)

A full-credit answer: Whole mitochondrial DNA sequences compare thousands of positions across many genes: many characters.
One protein compares a few positions in one gene.
A likeness at a few positions can arise by chance, or because the protein is shaped by selection for a shared way of life.
Thousands of positions almost never come to agree by chance, so the DNA tree is the more reliable.

Check the box for each point your answer earns

Accept one of the following: the DNA comparison uses many more positions (many genes) than one protein does, so it rests on many characters; a single protein can be shaped alike by selection (a shared way of life), so its likeness need not reflect ancestry; DNA sequences vary at more positions than the protein they code for, so they carry more information.

Scoring note: ‘DNA is more accurate’ with no reason does not earn the point.

Free-response score: 0 of 4
Free response 3 · Conceptual Analysis · 4 points
Suppose a kind of smooth snake, a small snake that keeps to the shrubs of a heath, once lived across one heath. About 250 years ago a stretch of the heath about 2 km wide was cleared for farmland, leaving a west heath and an east heath, and smooth snakes never cross open fields. Since the clearing, a larger kind of lizard has replaced the small lizard that the snakes eat on the east heath. Biologists read three genes in 50 snakes from each heath today and in 50 preserved specimens collected across the heath before the clearing, as Table 1 shows. Brought together in an enclosure, west snakes and east snakes mate, and their young grow up and breed.
Table 1, the frequency of one allele at each of three genes in the smooth snakes: in 50 preserved specimens collected before the clearing, in 50 west-heath snakes today and in 50 east-heath snakes today: head-width gene, allele F, 0.31, 0.29, 0.86; scale-pattern gene, allele P, 0.56, 0.71, 0.41; tail-length gene, allele L, 0.48, 0.27, 0.63gene and allelebefore the clearingwest heath todayeast heath todayhead-width gene, allele F0.310.290.86scale-pattern gene, allele P0.560.710.41tail-length gene, allele L0.480.270.63
Table 1. The frequency of one allele at each of three genes: before the clearing, and on each heath today.

(a) Describe the barrier that stopped gene flow between the west snakes and the east snakes. (1 point)

A full-credit answer: The stretch of farmland is a geographic barrier.
Smooth snakes never cross open fields, so no snake from one heath reaches the other to mate.
So no alleles pass between the two populations.

Check the box for each point your answer earns

Accept: a pre-zygotic mechanism, with the farmland named as what keeps the two apart (the course’s framing of a geographic barrier as a barrier of the kind a different habitat).

Scoring note: ‘they live far apart’ with no barrier named does not earn the point.

Common slip: Saying the farmland changed the snakes’ alleles. The barrier changes no alleles; it stops alleles passing between the two heaths.

(b) Smooth snakes with a wider head can swallow larger lizards. For the snakes of the east heath, explain the difference in fitness between wider-headed snakes and narrower-headed snakes. (1 point)

A full-credit answer: On the east heath the small lizard has been replaced by a larger lizard.
A wider-headed snake can swallow the larger lizard, so it eats more often.
A snake that eats more often survives and leaves more offspring.
So wider-headed snakes have the higher fitness on the east heath.

Check the box for each point your answer earns

Scoring note: ‘wider heads are better’ with no link to eating and reproducing does not earn the point.

(c) Suppose the farmland is abandoned and the heath’s shrubs grow back across the cleared stretch, so snakes can cross it again. Predict whether the west snakes and the east snakes will merge back into one population or stay two separate populations. (1 point)

A full-credit answer: The two will merge back into one population.

Check the box for each point your answer earns

Scoring note: ‘the two stay separate populations’ does not earn the point. Brought together, west snakes and east snakes mate and their young grow up and breed, so the two still interbreed.

Common slip: Predicting that the two stay separate because their allele frequencies differ. The frequencies show divergence; whether the two merge depends on whether they still interbreed.

(d) Justify your prediction in part (c). (1 point)

A full-credit answer: West snakes and east snakes still mate, and their young grow up and breed, so no reproductive isolating mechanism has formed.
Once the shrubs return, snakes cross the stretch and mate with snakes of the other heath.
Their fertile young carry alleles from both heaths, so alleles pass between the two again.
Over generations the differences in Table 1 shrink, and the two are one population.

Check the box for each point your answer earns

Scoring note: a justification of ‘stay separate’ earns nothing, however it is reasoned — from the allele frequencies that differ, or from the larger lizard still on the east heath. The enclosure result shows the two interbreed with fertile young, so no isolating mechanism has formed, and alleles pass again once snakes can cross. Differing frequencies are divergence; the species test is whether the two interbreed with fertile young.

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